\[ \newcommand{\d}{\text d} \newcommand{\dt}{\d t} \newcommand{\dN}{\d N} \]
For the two competition species with population number \(N_1, N_2\), the environment environmental capacity and instant growth rate are \(K_1, r_1, K_2, r_2\) respectively. For the species 1, based on Logistic equation, we have \[ \frac{\dN_1}{\dt} = r_1N_1\left( 1-\frac{N_1}{K_1}-\alpha\frac{N_2}{K_1} \right) \] where \(\alpha\) is the competition coefficient from species 2 to species 1, the physical meaning is “one animal of species 2 is the same as \(\alpha\) animals of species 1”. Similarly, for species 2 we have \[ \frac{\dN_2}{\dt} = r_2N_2\left( 1-\frac{N_2}{K_2}-\alpha\frac{N_1}{K_2} \right) \] where \(\alpha\) is the competition coefficient of species 1 to species 2.
The two equations give the Lotka-Volterra competition model.
We could use the reciprocal of capacity \(K^{-1}\) as the indicator of the intensity of intraspecific competition, and \(\alpha K_1^{-1}\) as the intensity of interspecific competition from species 2 to species 1, symmetrically, \(\beta K_2^{-1}\) as the intensity of interspecific completition from species 1 to species 2.
One species win in the interspecific competition, if and only if the intensity of interspecific completition larger than the intensity of intraspecific competition, that is
The detailed proof refers to 《基础生态学(第2版)》P133-P134↩︎